預估量有超過 5日均量或昨量5倍的股票

小幫手好

我想在盤中(5分鐘k線圖) 挑出 預估量有超過( 5日均量或昨量 )的5倍，且ma10. ma50向上，盤整後開高不拉回的股票，我套用了一些搜尋到的腳本，程式碼如下

但今天盤中啟動使用，卻篩出預估量、 5日均量、昨量有低於1000張的股票，可以幫我看哪裡有錯嗎?

 

input: shortlength(10); setinputname(1,"短期均線期數");

input: Longlength(50); setinputname(2,"長期均線期數");

variable: Longaverage(0);

variable: shortaverage(0);

Longaverage = Average(close,Longlength); //50

shortaverage= Average(close,shortlength) ; //10

 

 

input:sp(1);

input:opl(2);

input:oph(4);

setinputname(1,"回檔最大幅度");

setinputname(2,"漲幅最小幅度");

setinputname(3,"開高最大幅度");

value15=getfield("close", "d")[1]; //前一日的收盤價

value16=getfield("close", "d")[3];

 

 

value1= xf_xaverage("d",GetField("Volume", "D")[1], 5);

value5= xf_xaverage("D",GetField("Volume", "D")[1], 60);

value6=GetField("Volume", "D")[1];

 

value2=q_EstimatedTotalVolume;//GetField("估計量")

value3=summation(volume, 15)*8;//前十五根一分鐘線成交量的合計的8倍

 

condition1 = value1 > 1000 ;//五日均量大於1000張

condition7 = value6 > 1000 ;//昨量大於1000張

 

condition2 = value3 >= value1 * 5;//前十五根一分鐘線成交量合計的8倍大於五日均量5倍

condition4 = value3 >= value5 * 5;//前十五根一分鐘線成交量合計的8倍大於季均量5倍     

condition8 = value3 >= value6 * 5;//前十五根一分鐘線成交量合計的8倍大於昨量5倍

 

condition3 = value2 >= value1 *5;

condition5 = value2 >= value5 *5;

condition6 = value2 >= value6 *5;

 

 

if currentdate <> date then return;

if time = 090500 then 

    begin

        value11 = getfield("open","5")[1];//第一根5分K開盤價

        value12 = getfield("high","5")[1];//第一根5分K最高價

        value13 = getfield("low","5")[1];//第一根5分K最低價

        value14 = getfield("close","5")[1];//第一根5分K收盤價

    end;

 

if time>0905

then

begin

if close>=value15*(1+opl/100)//1.漲幅超過2%，但沒有超過4%。

and close<=value15*(1+oph/100)

and low>high*(1-sp/100)//2.九點五分之後 從最高價拉回幅度不超過1%。

and close=high//4.現在股價突破開盤價達今日最高價

and value15<value16*1.04//3.過去三天股價漲幅沒有超過4%

then ret=1;

end;

 

if condition1=true

and condition7=true

and (condition2 or condition3  or condition4  or condition5  or condition6 or condition8)

 

and Longaverage[0]>Longaverage[1]

and shortaverage[0]>shortaverage[1]

and shortaverage > Longaverage

and close > shortaverage

 

then ret=1;