較簡潔的寫法

VicHuang 發文於 2023/06/14

c[0]<=High[1] and c[0]<=High[2] and c[0]<=High[3] and c[0]<=High[4];

想請教上面這段有沒有較簡潔的寫法，感謝回覆

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bowen 發文於 2023/06/14

c[0]<=H[1] and c[0]<=H[2] and c[0]<=H[3] and c[0]<=H[4];

如果是因為後面要一直重複打可以寫:

condition1 = c[0]<=H[1] and c[0]<=H[2] and c[0]<=H[3] and c[0]<=H[4];

然後 if condition1 then .....

XQ小幫手發文於 2023/06/15

Hello VicHuang,

您可以參考bowen的作法。

另外也可以用迴圈的方式撰寫。

舉例來說:

value1 = 0;

for value2 = 1 to 4 begin

if close[0] <= high[value2] then value1 += 1;

end;

這樣 value1 就會是 c[0]<=High[1] and c[0]<=High[2] and c[0]<=High[3] and c[0]<=High[4] 這段中有符合條件的次數。

若要全部符合的話就是 condition1 = value1 = 4;。

感謝 bowen 的熱心回覆。

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