程式A
if ((high-low)/close[1])*100>2.5
and open > close
and close * volume > 145000
then ret=1 ;
=====================================
程式B
if (highd(0)-lowd(0))/closd(1)*100 >2.5
and opend(0) > closed(0)
and closed(0) * volume(0) > 145000
then ret=1 ;
程式A
if ((high-low)/close[1])*100>2.5
and open > close
and close * volume > 145000
then ret=1 ;
=====================================
程式B
if (highd(0)-lowd(0))/closd(1)*100 >2.5
and opend(0) > closed(0)
and closed(0) * volume(0) > 145000
then ret=1 ;
1 評論