小幫手您好,我參考教學和範例,想寫出符合底下幾樣條件,突破均線糾結的指令,可是似乎有問題,懇請指教,感謝
1.今日收盤價超過最高價均線至少 2%,且 今日收盤價 >= 昨天和前天的最高價
2.昨日收盤價 <= 前天 或者 大前天的最高價
3.由昨日開始往前推,總共13日均線糾結,這13天的每日最高價均線不超過最低價均線的 1%
底下是我的語法,請指點,很感謝
input:length_5MA(5,"MA1天期"),length_10MA(10,"MA2天期"),length_20MA(20,"MA3天期"),
MA_N1(2,"高於最高MA幾(%)以上"),MA_N2(10,"高於最高MA幾(%)以下"),MA_N3(1,"均線糾結幾(%)內");
value1 = average(close,length_5MA);
value2 = average(close,length_10MA);
value3 = average(close,length_20MA);
value4 = maxlist(value1,value2,value3);
value5 = minlist(value1,value2,value3);
if close >= value4 * ( 1+ 0.02 * MA_N1)
and close[1] <= high[2] or close[1] <= high[3]
and close >= High[1]
and close >= high[2]
and value4[1] <= value5[1] * (1+0.01 * MA_N3)
and value4[2] <= value5[2] * (1+0.01 * MA_N3)
and value4[3] <= value5[3] * (1+0.01 * MA_N3)
and value4[4] <= value5[4] * (1+0.01 * MA_N3)
and value4[5] <= value5[5] * (1+0.01 * MA_N3)
and value4[6] <= value5[6] * (1+0.01 * MA_N3)
and value4[7] <= value5[7] * (1+0.01 * MA_N3)
and value4[8] <= value5[8] * (1+0.01 * MA_N3)
and value4[9] <= value5[9] * (1+0.01 * MA_N3)
and value4[10] <= value5[10] * (1+0.01 * MA_N3)
and value4[12] <= value5[11] * (1+0.01 * MA_N3)
and value4[12] <= value5[12] * (1+0.01 * MA_N3)
and value4[13] <= value5[13] * (1+0.01 * MA_N3) then ret = 1;
1 評論